1/25-16z^2=0

Solution for 1/25-16z^2=0 equation:

1/25-16z^2=0

We multiply all the terms by the denominator


-16z^2*25+1=0

Wy multiply elements

-400z^2+1=0

a = -400; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-400)·1
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*-400}=\frac{-40}{-800}
=1/20
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*-400}=\frac{40}{-800}
=-1/20
$